JEE Main & Advanced Sample Paper JEE Main - Mock Test - 29

  • question_answer
    A carrier frequency of 1 MHz and peak value of 10 V is amplitude modulated with a signal frequency of 10 kHz with peak value of 0.5 V. Then the modulation index and the side band frequencies respectively are

    A)  0.05 and \[1\pm 0.010\text{ }MHz\]

    B)  0.5 and \[1\pm 0.010\text{ }MHz\]

    C)  0.05 and \[1\pm 0.005\text{ }MHz\]

    D)  0.5 and \[1\pm 0.005\text{ }MHz\]

    Correct Answer: A

    Solution :

    [a]: Modulation index, \[\mu =\frac{{{A}_{m}}}{{{A}_{c}}}\] \[\mu =\frac{0.5V}{10V}=0.05\] The side bands frequencies are\[{{\upsilon }_{SB}}={{\upsilon }_{c}}\pm {{\upsilon }_{m}}\] \[=(1\pm 0.010)MHz\]


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