A) Dissociate to the extent of\[50%\]
B) Hydrolyse to the extent of \[80%\]
C) Dimerize to the extent of \[50%\]
D) Trimerise to the extent of \[75%\]
Correct Answer: D
Solution :
[d] \[\underset{(p\,\,moles)}{\mathop{KCl}}\,\] and \[\underset{(p\,\,moles)}{\mathop{X}}\,\] \[\Delta {{T}_{f}}(KCl)=i{{K}_{f}}m=2{{K}_{f}}m\]\[\Delta {{T}_{f}}(X)=i{{K}_{f}}m=\frac{1}{4}(2{{K}_{f}}m)\Rightarrow i=\frac{\alpha }{2}(<1)\] \[\underset{1-\alpha }{\mathop{\underset{1}{\mathop{2X}}\,}}\,\underset{\alpha /2}{\mathop{\underset{0}{\mathop{{{X}_{2}}}}\,}}\,\] \[i=1-\alpha +\frac{\alpha }{2}=1-\frac{\alpha }{2}\Rightarrow \alpha =100%\] \[\underset{1-\alpha }{\mathop{\underset{1}{\mathop{3X}}\,}}\,\underset{\alpha /3}{\mathop{\underset{0}{\mathop{{{X}_{3}}}}\,}}\,\] \[i=1-\alpha +\frac{\alpha }{3}=1-\frac{2\alpha }{3}=\frac{\alpha }{2}\Rightarrow \alpha \frac{3}{4}=75%\]
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