A) 1.25 m
B) 2.50 m
C) 3.75 m
D) 5.00 m
Correct Answer: C
Solution :
[c] : Let T be the time interval between the drops (1, 2, 3) falling from the tap as shown in the figure. Since distance covered by the first drop in time 2T is 5m,\[5=\frac{1}{2}g{{(2T)}^{2}}=2g{{T}^{2}}\] ...(i) Further, distance covered by the second drop in time T (from t = T to t = 2T), \[y=\frac{1}{2}g{{T}^{2}}\] ...(ii) From eqns. (i) and (ii), y = 1.25 m Distance of the second drop from the ground \[=5-=5-1.25=3.75m\]You need to login to perform this action.
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