A) u
B) 10 u
C) 100 u
D) 1000 u
Correct Answer: B
Solution :
[b]: Surface energy\[u=S\times 4\pi {{R}^{2}}\] When droplet is splitted into 1000 droplets each of radius r, then\[\frac{4}{3}\pi {{R}^{3}}=1000\frac{4}{3}\pi {{r}^{3}}\Rightarrow r=\frac{R}{10}\] Here, R is the radius of bigger drop and 5 is the surface tension. \[\therefore \]Surface energy of all droplets \[=S\times 1000\times 4\pi {{r}^{2}}=S\times 1000\times 4\pi {{(R/10)}^{2}}\] \[=10(S4\pi {{R}^{2}})=10u\]
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