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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 2

  • question_answer
    The number of isomers for the complexes X and Y are, respectively, \[X={{[Pt(N{{H}_{3}})(N{{H}_{2}}OH)(N{{O}_{2}})(py)]}^{\oplus }}\] \[Y=\left[ Cr \right[\left( N{{H}_{3}} \right){{\left( OH \right)}_{2}}C{{l}_{3}}]\]

    A) 2 and 3

    B) 3 and 3        

    C) 3 and 4              

    D) 4 and 3

    Correct Answer: B

    Solution :

       [b] For X:- \[{{[Mabcd]}^{n\pm }}:\]: For complexes with general formula Mabcd, three geometrical isomers [a], [b] and [c] are possible.
      A B C
    \[a-b\] cis trans cis
    \[c-d\] cis trans cis
    \[a-d\] cis cis trans
    \[a-c\] trans cis cis
    \[b-d\] trans cis cis
    For example \[{{[P{{t}^{+2}}(N{{H}_{3}})\,(N{{H}_{2}}OH)\,(N{{O}_{2}})\,(py)]}^{\oplus }}\,\,N{{O}_{2}}^{\Theta }\] For Y:- \[CN=6\] Geometry is octahedral. Three isomers are possible. I.  II. III.    


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