A) 4, 4 and 6
B) 5, 5 and 7
C) 6, 6 and 4
D) 7, 5 and 5
Correct Answer: A
Solution :
[a] Blue vitriol: \[\begin{align} & CuS{{O}_{4}}.5{{H}_{2}}O \\ & \Downarrow \\ & {{\left[ \overset{2+}{\mathop{Cu}}\,{{({{H}_{2}}O)}_{4}} \right]}^{+2}}S{{O}_{4}}^{-2}.{{H}_{2}}O \\ \end{align}\] White vitriol: \[ZnS{{O}_{4}}.5{{H}_{2}}O\Rightarrow \] \[{{\left[ \overset{+2}{\mathop{Zn}}\,{{({{H}_{2}}O)}_{4}} \right]}^{+2}}SO_{4}^{2-}.{{H}_{2}}O\] Green vitriol: \[FeS{{O}_{4}}.7{{H}_{2}}O\Rightarrow \] \[{{\left[ \overset{+2}{\mathop{Fe}}\,{{({{H}_{2}}O)}_{6}} \right]}^{+2}}SO_{4}^{2-}{{H}_{2}}O\] Coordination number of \[C{{u}^{+2}},\,Z{{n}^{+2}},\] and \[F{{e}^{+2}}\] are 4, 4 and 6 respectively
You need to login to perform this action.
You will be redirected in
3 sec
