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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 2

  • question_answer
    The quantum number of the last electron of an element are given below. Predict the atomic number and name of the element from the following quantum numbers \[n=3,l=2,m=0,s=-\frac{1}{2}\]

    A) 23, V                 

    B) 21, Sc                 

    C) 29, Cu                   

    D) 28, Ni

    Correct Answer: D

    Solution :

    [d]
    \[n=3\] \[l=2,\] \[3d\]
    \[m=-2\] \[-1\] \[0\] \[+1\] \[+2\]  
    \[{{d}_{{{x}^{2}}-{{y}^{2}}}}\] \[{{d}_{xy}}\] \[{{d}_{{{z}^{2}}}}\] \[{{d}_{zx}}\] \[{{d}_{xy}}\]  
    or or or or or  
    \[{{d}_{xy}}\] \[{{d}_{zx}}\] \[{{d}_{{{z}^{2}}}}\] \[{{d}_{yz}}\] \[{{d}_{{{x}^{2}}-{{y}^{2}}}}\]  
    \[s=+\frac{1}{2}\]
              \[s=-\frac{1}{2}\]
                                                     Structure is \[3{{d}^{8}}\]   Atomic number = 28 The element is\[Ni\].


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