JEE Main & Advanced Sample Paper JEE Main - Mock Test - 2

  • question_answer
    From the data given below, which of the following is most effective drying agent at\[0{}^\circ C\].
    I. \[SrC{{l}_{2}}\cdot 6{{H}_{2}}O(s)\rightleftharpoons SrC{{l}_{2}}\cdot 2{{H}_{2}}O(s)+4{{H}_{2}}O(g)\]
        \[{{K}_{p}}={{10}^{-12}}at{{m}^{4}}\]
    II. \[N{{a}_{2}}HP{{O}_{4}}\cdot 12{{H}_{2}}O(s)\rightleftharpoons N{{a}_{2}}HP{{O}_{4}}\cdot 7{{H}_{2}}O(s)+5{{H}_{2}}O(g)\]
        \[{{K}_{p}}=5.25\times {{10}^{-13}}at{{m}^{5}}\]
    III. \[N{{a}_{2}}S{{O}_{4}}\cdot 10{{H}_{2}}O(s)\rightleftharpoons N{{a}_{2}}S{{O}_{4}}(s)+10{{H}_{2}}O(g)\]
        \[{{K}_{p}}=4.08\times {{10}^{-25}}at{{m}^{10}}\]  
    Given: The vapour pressure of water (i,e., \[P({{H}_{2}}O)at\,0{}^\circ C=6.0\times {{10}^{-3}}atm\]

    A) \[SrC{{l}_{2}}.2{{H}_{2}}O\] 

    B) \[N{{a}_{2}}HP{{O}_{4}}.7{{H}_{2}}O\]

    C) \[N{{a}_{2}}S{{O}_{4}}\]              

    D) All of these

    Correct Answer: A

    Solution :

    [a] \[{{K}_{p}}=P{{({{H}_{2}}O)}^{4}}={{10}^{-12}},\,\,P({{H}_{2}}O)={{10}^{-3}}\]atm. Therefore \[SrC{{l}_{2}}.2{{H}_{2}}O\] (dehydrated salt) is the most effective drying agent, since it has the lowest vapour pressure of water in equilibrium with it amongst others.


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