A) \[29(x-2)+27(y+1)-22z=0\]
B) \[29(x-2)-27(y+1)-22z=0\]
C) \[29(x-2)+27(y+1)+22z=0\]
D) None of these
Correct Answer: B
Solution :
| Any plane passing through \[(2,-1,0)\]is \[a(x-2)+b(y+1)+cz=0;\] | ...[a] |
| It will pass through \[(3,-4,5)\] if \[a-3b+5c=0\] | ...[b] |
| Also [a] will be parallel to \[2x=3y=4z,\] i.e, \[\frac{x}{\frac{1}{2}}=\frac{y}{\frac{1}{3}}=\frac{z}{\frac{1}{4}}\] | |
| If \[a.\frac{1}{2}+b.\frac{1}{3}+c.\frac{1}{4}=0\]or \[6a+4b+3c=0\] | ?[c] |
| From (b) and (c), \[\frac{a}{-9-20}=\frac{b}{30-3}=\frac{c}{4+18}\] | |
| i.e, \[\frac{a}{29}=\frac{b}{-27}=\frac{c}{-22}\] | |
| Hence the plane is \[29(x-2)-27(y+1)-22z=0\] | |
You need to login to perform this action.
You will be redirected in
3 sec
