A) \[h+\frac{{{P}_{0}}rh}{2T-\rho ghr}\]
B) \[h+\frac{{{P}_{0}}rh}{T-\rho ghr}\]
C) \[h+\frac{{{P}_{0}}rh}{2T+\rho ghr}\]
D) \[h+\frac{{{P}_{0}}rh}{T+\rho ghr}\]
Correct Answer: A
Solution :
[a] When the tube is brought into contact with water, it is filled with air at atmospheric pressure. When water rises to a height h, the air pressure (P) is given by \[PA(L-h)={{P}_{0}}AL.\] \[\therefore \,\,\,\,\,\,\,P=\frac{{{P}_{0}}L}{L-h}\]You need to login to perform this action.
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