question_answer

A particle of mass \[2m\] is projected at an angle of \[45{}^\circ \] with horizontal with a velocity of \[20\sqrt{2}m/s\] . After 1 s explosion takes place and the particle is broken into two equal pieces. As a result of explosion one part comes to rest. What is the maximum height (in m) from the ground attained by the other part? \[(g=10m/{{s}^{2}})\]

Answer:

35