A) \[2KI+B{{r}_{2}}\to \,\,2KBr+{{I}_{2}}\]
B) \[2KBr+{{I}_{2}}\to 2KI+B{{r}_{2}}\]
C) \[2KBr+C{{l}^{2}}\to 2KCl+B{{r}_{2}}\]
D) \[2{{H}_{2}}O+2{{F}_{2}}\to 4HF+{{O}_{2}}\]
Correct Answer: B
Solution :
\[2\,KBr+{{I}_{2}}\,\,\xrightarrow{{}}\,\,2KI\,\,+B{{r}_{2}}\] This reaction is not possible because \[B{{r}^{-}}\] ion is not oxidised in \[{{\operatorname{Br}}_{2}}\,with {{I}_{2}}\] due to higher electrode (oxidation) potential of \[{{I}_{2}}\] than bromine.
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