JEE Main & Advanced
Sample Paper
JEE Main - Mock Test - 30
question_answer
The densities of graphite and diamond at 298 K are 2.25 and \[3.31 g cm{{\,}^{-3}}\], respectively. If the standard free energy difference \[(\Delta G{}^\circ )\] is equal to \[1895 J mol{{\,}^{-}}^{1}\], the pressure at which graphite will be transformed into diamond at 298 K is
Answer:
\[\left( 11.09\times 1{{0}^{8}} \right)\Delta G = - P\Delta V= Work done\]