A) \[CC{{l}_{4}}\]
B) \[SiC{{l}_{4}}\]
C) \[PbC{{l}_{2}}\]
D) \[PbC{{l}_{4}}\]
Correct Answer: C
Solution :
\[PbC{{l}_{2}}\] is most ionic because on going down the group the metallic character increases and also the inert pair effect predominates. Between \[{{\operatorname{PbCl}}_{2}}\,\,and\,\,PbC{{l}_{4}}\,\,PbC{{l}_{2}}\] is more ionic according to Fajan?s rule.
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