A) \[2a\sin \frac{\alpha }{2}\tan \alpha \]
B) \[2a\cos \frac{\alpha }{2}\tan \alpha \]
C) \[2asin\frac{\alpha }{2}\cot \alpha \]
D) \[2a\cos \frac{\alpha }{2}\cot \alpha \]
Correct Answer: A
Solution :
[a] \[AB=2a\,\,\sin \frac{\alpha }{2}\] In \[\Delta ABC,\] \[\tan \alpha =\frac{AC}{AB}\] \[\therefore \,\,\,\,AC=2a\,\,\sin \frac{\alpha }{2}\tan \alpha \]You need to login to perform this action.
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