A) \[\frac{4}{5}\times {{10}^{6}}\]
B) \[2\times {{10}^{6}}\]
C) \[8\times {{10}^{6}}\]
D) \[2\times {{10}^{7}}\]
Correct Answer: C
Solution :
[c] \[\frac{1}{2}m{{V}^{2}}=h\left( v-{{v}_{0}} \right)\] Case I: v = 2vo \[\frac{1}{2}m{{V}_{1}}^{2}=h{{v}_{0}}\] ...(1) for \[V=5{{v}_{0}}\] \[\frac{1}{2}m{{V}_{2}}^{2}=4h{{v}_{0}}\] ...(2) (2)\[\div \](1) \[{{V}_{2}}^{2}=4{{V}_{1}}\] or \[{{V}_{2}}=2{{V}_{1}}\] \[=2\times 4\times {{10}^{6}}=8\times {{10}^{6}}\]You need to login to perform this action.
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