A) \[y=A\,sin\left( kx+\omega t \right)\]
B) \[y=A\,\cos \left( kx+\omega t \right)\]
C) \[y=-A\,sin\left( kx-\omega t \right)\]
D) \[y=-A\,sin\left( kx+\omega t \right)\]
Correct Answer: D
Solution :
[d]\[y=A\,sin\left( kx-\omega t \right)\] for the wave progressing along the x-axis and for the reflected wave. \[y'=A\,sin\left( kx+\omega t \right).\] But the position of the rigid wall is at\[x=0\]. \[\therefore \] For the given wave, its reflected wave \[y'=-A\,sin\left( kx+\omega t \right)\]You need to login to perform this action.
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