A) 10.0
B) 9.0
C) 6.0
D) 8.0
Correct Answer: A
Solution :
The pOH of a buffer consisting of \[N{{H}_{3}}\] (i.e. \[N{{H}_{4}}OH\]) and salt \[N{{H}_{4}}Cl\] (salt) is given by the equation \[pOH=p{{K}_{b}}+\log \frac{\left[ ammonia \right]}{\left[ salt \right]}=5.0+\log \,\frac{\left[ 0.1 \right]}{\left[ 1.0 \right]}\] \[=5.0 -log 10 =5-1=4.0\] \[\therefore \,\,pH= 14-pOH= 14-4.0= 10\]You need to login to perform this action.
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