A) \[1.05\times {{10}^{-}}^{34}\]
B) \[2.1\times {{10}^{-}}^{34}\]
C) \[3.15\times {{10}^{-}}^{34}\]
D) \[~-\,2.1\times {{10}^{-}}^{34}\]
Correct Answer: C
Solution :
Energy of electron in H atom \[{{E}_{n}}=\frac{-13.6}{{{n}^{2}}}eV\] \[\Rightarrow \,\,\,-1.5=\frac{-13.6}{{{n}^{2}}}\,\,\Rightarrow \,\,{{n}^{2}}=\frac{13.6}{1.5}=3\] Now angular momentum \[L=n\frac{h}{2\pi }=\frac{3\times 6.6\times {{10}^{-34}}}{2\times 3.14}=3.15\times {{10}^{-34}}\,J-s\]
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