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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 32

  • question_answer
    One conducting C/tube can slide inside another as shown in figure, maintaining electrical contacts between the tubes. The magnetic field B is perpendicular to the plane of the figure. If each tube moves towards the other at a constant speed v then the emf induced in the circuit in terms of B, I and v where / is the width of each tube, will be

    A) Zero                 

    B)        \[2\,Bl\nu \]

    C) \[Bl\nu \]                       

    D)        \[-\,Bl\nu \]

    Correct Answer: B

    Solution :

    Two emfs are induce in the closed circuit each of value Blv. These two emfs are additive. So\[{{E}_{net}}=2Bl\nu \].


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