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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 32

  • question_answer
    Two equal masses of 6.40 kg each are separated by a distance of 0.16 m. A small body is released from a point P equidistant from the two masses and at a distance 0.06 m from the line joining them as shown in fig. Calculate the velocity (in m/s) of this body when it passes through Q.

    Answer:

    \[\operatorname{v}=6.53\times {{10}^{-5}}m/sec.\]


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