A) \[{{p}_{1}}={{p}_{2}}\]
B) \[{{p}_{1}}>{{p}_{2}}\]
C) \[{{p}_{2}}>{{p}_{1}}\]
D) \[{{p}_{1}}=1\,\,atm\]
Correct Answer: C
Solution :
[c] Cell is spontaneous when\[{{p}_{2}}\] (cathode) \[>{{p}_{1}}\](anode) \[\underset{\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}{\mathop{\begin{matrix} At\,\,anode:\,\,\,2C{{l}^{\Theta }}\,(0.1M)\xrightarrow{{}}C{{l}_{2}}({{p}_{1}})+2{{e}^{-}} \\ \underset{\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}{\mathop{At\,\,cathode:\,\,C{{l}_{2}}({{p}_{2}})+2{{e}^{-}}\xrightarrow{{}}2C{{l}^{\Theta }}\,(0.1M)}}\, \\ Cell\,\,reaction:\,\,\,C{{l}_{2}}({{p}_{2}})\xrightarrow{{}}C{{l}_{2}}({{p}_{1}}) \\ \end{matrix}}}\,\] \[{{E}_{cell}}={{E}^{\Theta }}_{Cell}-\frac{0.059}{2}\log \frac{{{p}_{1}}}{{{p}_{2}}}\] \[=0+\frac{0.059}{2}\log \frac{{{p}_{2}}}{{{p}_{1}}}\] \[{{E}_{cell}}>0\] if \[{{p}_{2}}>{{p}_{1}}.\]
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