A) {-2, 2, 1, 3}
B) {-2, 0, 3}
C) {-2, 2, 0}
D) {1, 3}
Correct Answer: D
Solution :
[d] \[f\left( x \right)=\left( x+2 \right)\left( x-2 \right)|\left( x-1 \right)\left( x-2 \right)\left( x-3 \right)|+\frac{x}{1+|x|}\]\[\left( y-1 \right)(x-2)\left( x-3 \right)\] is not differentiable at x= 1,3 only. \[\frac{x}{1+|x|}\] is always differentiable.You need to login to perform this action.
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