A) \[\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}\]
B) \[\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{e}^{2}}}{{{d}^{2}}}}\]
C) \[\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}}\]
D) \[\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{q}^{2}}}\]
Correct Answer: C
Solution :
Let n be the number of electrons missing. \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{{{q}^{2}}}{{{d}^{2}}}\,\,\,\,\Rightarrow \,\,q=\sqrt{4\pi {{\varepsilon }_{0}}{{d}^{2}}F}=ne\]\[\therefore \,\,\,n=\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}}\]
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