A) 0.109
B) 0.218
C) 1.89
D) 2.18
Correct Answer: A
Solution :
[a] \[\underset{-}{\mathop{N{{H}_{4}}HS(s)}}\,\underset{P}{\mathop{N{{H}_{3}}(g)}}\,+\underset{P}{\mathop{{{H}_{2}}S(g)}}\,\] Equ. pressure 2P = 0.660 P= 0.330 \[Kp={{P}_{N{{H}_{3}}}}.{{P}_{{{H}_{2}}S}}\] \[=0.33\times 0.33=0.109\]You need to login to perform this action.
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