A) 6
B) 1
C) -1
D) - 5
Correct Answer: D
Solution :
The given expression (limit) is of \[\frac{0}{0}\] form. So, L? Hopital rule is applicable \[\therefore \,\,\,Given\,\,is\,\,\underset{x\to a}{\mathop{\lim }}\,\frac{f(a)g'(x)-g(a)f'(x)}{1}\] (By L/ Hospital?s Rule) \[=\,\,\underset{x\to a}{\mathop{\lim }}\,\frac{2g'(x)-3f'(x)}{1}=2g'(a)-3f'(a)\] \[=2\left( -1 \right)-3\left( 1 \right)=-\,5\]You need to login to perform this action.
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