A) \[a=b=c=0\]
B) \[a=0,\,\,b=0,\,\,c\in R\]
C) \[b=c=0,\,\,a\in R\]
D) \[c=0,a=0,\,\,b\in R\]
Correct Answer: A
Solution :
Given \[\operatorname{f}(x)=\,\,a\left| sin\,x \right|\,+\,b{{e}^{\left| x \right|}}\,+\,\,c{{\left| x \right|}^{3}}\] Since, \[\left| x \right|\] is non-differentiable at \[\operatorname{x} =0\] \[\therefore \,\,\,f(x)\] cannot be differentiable at \[x= 0\] Hence, \[\operatorname{a}=b= c = 0.\]You need to login to perform this action.
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