A) \[C{{u}^{+2}}\]
B) \[T{{i}^{+3}}\]
C) \[N{{i}^{+2}}\]
D) \[M{{n}^{+2}}\]
Correct Answer: D
Solution :
[d] \[C{{u}^{+2}}=\left[ Ar \right]4{{s}^{0}}3{{d}^{9}}\left( 1\text{ }unpaired\text{ }{{e}^{-}} \right)\] \[T{{i}^{+3}}=[Ar]4{{s}^{0}}3{{d}^{1}}(1\,unpaired\,e{{~}^{-}})\] \[N{{i}^{+2}}=[Ar]4{{s}^{0}}3{{d}^{8}}(2\,unpaired\,{{e}^{-}})\] \[M{{n}^{+2}}=[Ar]4{{s}^{0}}3{{d}^{5}}(5\,unpaired\,{{e}^{-}})\]You need to login to perform this action.
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