A) Becomes zero instantaneously
B) Grows monotonically
C) Decays monotonically
D) Oscillates instantaneously
Correct Answer: D
Solution :
[d] \[\frac{q}{c}+L\frac{di}{di}=0\Rightarrow \,\frac{{{d}^{2}}q}{d{{t}^{2}}}+\frac{q}{LC}=0\] which is equation of oscillatory motion \[\Rightarrow \,\,\,\,\,q={{q}_{0}}\sin \omega t\Rightarrow \frac{dq}{dt}=i={{q}_{0}}\omega \cos \omega t\] here \[\omega =\frac{1}{\sqrt{LC}}\Rightarrow \] current starts oscillation.You need to login to perform this action.
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