A)
B)
C)
D)
Correct Answer: C
Solution :
\[\operatorname{CuS}{{O}_{4}}+4N{{H}_{4}}OH\,\xrightarrow{{}}\,\underset{Intense\,\,blue\,\,colour}{\mathop{{{\left[ Cu{{(N{{H}_{3}})}_{4}} \right]}^{2+}}}}\,\] \[+SO{{_{4}^{2-}}^{~}}+\,\,2{{H}_{2}}O\]You need to login to perform this action.
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