A) \[\sqrt{\frac{2k}{ma}}\]
B) \[\sqrt{\frac{k}{ma}}\]
C) \[\sqrt{\frac{4k}{ma}}\]
D) \[\sqrt{\frac{k}{2ma}}\]
Correct Answer: A
Solution :
[a] \[F=-\frac{k}{{{x}^{2}}}\] \[v.\frac{dv}{dx}=\frac{-k}{m{{x}^{2}}}\] \[\int\limits_{0}^{v}{v.dv}=\int\limits_{a}^{-a/2}{\frac{k}{m{{x}^{2}}}}\,\,dx\] \[v=\sqrt{\frac{2k}{ma}}\]You need to login to perform this action.
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