A) 3,-2
B) -3, 2
C) -6,-1
D) 6,-1
Correct Answer: D
Solution :
[d] Let quadratic equation \[={{x}^{2}}+bx-6=0\] constant term = wrong \[\Downarrow \] wrong roots = 3, 2 but sum of roots =3+2 It means, \[3+2=\frac{-b}{1}\] b = -5 correct \[\Rightarrow \]\[{{x}^{2}}-5x-6=0\] \[\left( x+1 \right)\left( x-6 \right)=0\] \[x=-1,\text{ }6\] rootsYou need to login to perform this action.
You will be redirected in
3 sec