A) \[{{K}_{3}}Fe{{\left( CN \right)}_{6}}\]
B) \[F{{e}_{4}}{{\left[ Fe{{\left( CN \right)}_{6}} \right]}_{3}}\]
C) \[Fe{{\left( OH \right)}_{3}}\]
D) \[KFe[Fe{{\left( CN \right)}_{6}}]\]
Correct Answer: B
Solution :
[b] \[\underset{\left( Prussian\text{ }blue \right)}{\mathop{F{{e}^{+3}}+{{K}_{4}}[Fe{{(CN)}_{6}}]}}\,\to F{{e}_{4}}{{[Fe{{(CN)}_{6}}]}_{3}}\]
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