A) \[2.144\text{ }g/c{{m}^{3}}\]
B) \[5.188\text{ }g/c{{m}^{3}}\]
C) \[7.289\text{ }g/c{{m}^{3}}\]
D) \[10.376\text{ }g/c{{m}^{3}}\]
Correct Answer: B
Solution :
[b] \[\rho =\frac{Z\times {{M}_{W}}}{{{N}_{A}}\times V}=\frac{2\times 100}{6\times {{10}^{23}}\times {{(400\times {{10}^{-10}})}^{3}}}\] \[=5.188g/c{{m}^{3}}\]
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