A) 5 F
B) 10 F
C) 20 F
D) None of these
Correct Answer: C
Solution :
[c] 1 mole \[M{{n}_{3}}{{O}_{4}}\,lose\text{ }\left( 6-\frac{8}{3} \right)\times 3=10\text{ }mole\text{ }{{e}^{-}}\]; so total charge required \[=2\times 10=20\text{ }F\]You need to login to perform this action.
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