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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 36

  • question_answer
    Consider the following reaction \[{{N}_{2}}(g)+3{{H}_{2}}(g)2N{{H}_{3}}(g);\,{{K}_{1}}\] \[{{N}_{2}}(g)+{{O}_{2}}(g)2O(g);\,{{K}_{2}}\] \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g){{H}_{2}}O(g);\,{{K}_{3}}\] The equilibrium constant for \[2N{{H}_{3}}(g)+\frac{5}{2}{{O}_{2}}(g)2NO(g)+3{{H}_{2}}O(g)\] will be-

    A) \[{{K}_{1}}{{K}_{2}}{{K}_{3}}\]       

    B)        \[\frac{{{K}_{1}}{{K}_{2}}}{{{K}_{3}}}\]

    C) \[\frac{{{K}_{1}}K_{3}^{2}}{{{K}_{2}}}\]    

    D)        \[\frac{{{K}_{2}}K_{3}^{2}}{{{K}_{1}}}\]

    Correct Answer: D

    Solution :

    [d] \[{{K}_{1}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}};{{K}_{2}}=\frac{{{[NO]}^{2}}}{[{{N}_{2}}][{{O}_{2}}]};{{K}_{2}}=\frac{[{{H}_{2}}O]}{[{{H}_{2}}]{{[{{O}_{2}}]}^{1/2}}}\] The equilibrium constant for \[2N{{H}_{3}}(g)+\frac{5}{2}{{O}_{2}}(g)2NO(g)+3{{H}_{2}}O(g)\] will be \[K=\frac{{{[NO]}^{2}}{{[{{H}_{2}}O]}^{3}}}{{{[N{{H}_{3}}]}^{2}}{{[{{O}_{2}}]}^{5/2}}}=\frac{{{K}_{2}}\times K_{3}^{3}}{{{K}_{1}}}\]


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