A) \[\frac{1}{4\pi {{\in }_{0}}}\frac{qQ}{d(d+L)}\]
B) \[\frac{qQ}{4\pi {{\in }_{0}}d}\]
C) \[\frac{qQ}{2\pi {{\in }_{0}}d}\]
D) \[\frac{qQ}{8\pi {{\in }_{0}}d(d+L)}\]
Correct Answer: A
Solution :
[a] \[dF=\frac{kqdQ}{{{x}^{2}}}=\frac{kq}{{{x}^{2}}}\frac{Q}{L}dx\] \[F=\int\limits_{x=d}^{x=d+L}{dF}\]You need to login to perform this action.
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