(I) \[MeCH=C{{H}_{2}}\] |
(II) \[PhCH=C{{H}_{2}}\] |
(III) \[C{{H}_{2}}=CH-COOMe\] |
(IV) \[C{{H}_{2}}=CH-Cl\] |
A) \[I>II>III>IV\]
B) \[II>I>IV>III\]
C) \[III>IV>I>II\]
D) \[II>IV>III>I\]
Correct Answer: B
Solution :
[b] Cationic polymerisation is favoured by EDGYou need to login to perform this action.
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