Column I | Column II | ||
I. | P. | ||
II. | Q. | ||
III. | R. | ||
IV. | S. |
A) I - Q II - P III - R IV - S
B) I - P II - Q III - R IV - S
C) I - R II - P III - S IV - Q
D) I - S II - R III - Q IV - P
Correct Answer: A
Solution :
[a] (I) It is an example of Hofmann exhaustive elimination, it gives less-substituted alkene. (II) Elimination of RX (except RF) with non-bulky base gives Saytzeff alkene (more substituted) but with bulky base gives Hofmann alkene (less substituted). (III) It is an example of Cope reaction. It gives less-substituted alkene. (IV). Same explanation as in (II) above.You need to login to perform this action.
You will be redirected in
3 sec