A) 5
B) 4
C) 7
D) 3
Correct Answer: C
Solution :
\[V=\frac{{{V}_{0}}}{T/4}t\,\,\,\,\,\,\,\,\Rightarrow \,\,\,V=\frac{4{{V}_{0}}}{T}t\] \[\Rightarrow \,\,\,{{V}_{rms}}=\sqrt{<{{V}^{2}}>}=\frac{4{{V}_{0}}}{T}\sqrt{<{{t}^{2}}>}=\,\,\frac{4{{V}_{0}}}{T}\left\{ \frac{\int\limits_{0}^{T/4}{{{t}^{2}}dt}}{\int\limits_{0}^{T/4}{dt}} \right\}\,\,=\,\,\frac{{{V}_{0}}}{\sqrt{3}}\]
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