A) \[\frac{{{\in }_{{{r}_{1}}}}}{{{\in }_{{{r}_{2}}}}}=4\]
B) \[\frac{{{\in }_{{{r}_{1}}}}}{{{\in }_{{{r}_{2}}}}}=2\]
C) \[\frac{{{\in }_{{{r}_{1}}}}}{{{\in }_{{{r}_{2}}}}}=\frac{1}{4}\]
D) \[\frac{{{\in }_{{{r}_{1}}}}}{{{\in }_{{{r}_{2}}}}}=\frac{1}{2}\]
Correct Answer: C
Solution :
Velocity of EM wave is given by \[v=\frac{1}{\sqrt{\mu \in }}\] Velocity in air \[=\,\,\frac{\omega }{k}=C\] Velocity in medium \[=\,\,\frac{C}{2}\] Here, \[{{\mu }_{1}}={{\mu }_{2}}=1\] as medium is non-magnetic \[\therefore \,\,\frac{\sqrt{\frac{1}{\sqrt{{{\in }_{{{r}_{1}}}}}}}}{\sqrt{\frac{1}{{{\in }_{{{r}_{2}}}}}}}=\frac{C}{\left( \frac{C}{2} \right)}=2\,\,\,\,\,\,\Rightarrow \,\,\,\frac{{{\in }_{{{r}_{1}}}}}{{{\in }_{{{r}_{2}}}}}=\frac{1}{4}\]You need to login to perform this action.
You will be redirected in
3 sec