question_answer

Five identical metal plates each of area A are held parallel to each other with successive separation d as shown in figure. The effective capacitance of the system between points P and Q is  

A) \[2{{\varepsilon }_{0}}A/d\]      

B)        \[3{{\varepsilon }_{0}}A/d\]

C) \[2{{\varepsilon }_{0}}A/3d\]     

D)        \[3{{\varepsilon }_{0}}A/2d\]

Correct Answer: D

Solution :

  As encircled capacitor is short circuited Hence, \[{{C}_{PQ}}=\frac{{{\varepsilon }_{0}}A}{d}+\frac{{{\varepsilon }_{0}}A}{2d}=\frac{3{{\varepsilon }_{0}}A}{2d}\]