| Column I | Column II | ||
| I. | | P. | |
| II. | | Q. | |
| III. | | R. | |
| IV. | | S. | |
A) I - Q II - P III - R IV - S
B) I - P II - Q III - R IV - S
C) I - R II - P III - S IV - Q
D) I - S II - R III - Q IV - P
Correct Answer: A
Solution :
[a] (I) It is an example of Hofmann exhaustive elimination, it gives less-substituted alkene.
(II) Elimination of RX (except RF) with non-bulky base gives Saytzeff alkene (more substituted) but with bulky base gives Hofmann alkene (less substituted). (III) It is an example of Cope reaction. It gives less-substituted alkene.
(IV). Same explanation as in (II) above.
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