question_answer

It is given that \[{{m}_{H}}=1.007825\,amu,\]\[{{m}_{n}}=1.008665\text{ }amu,\] mass of iron \[{{(}_{26}}F{{e}^{56}})=55.934939\,amu,\]mass of bismuth \[{{(}_{83}}B{{i}^{209}})=208.980388\,amu.\]What is the ratio of binding energy per nucleon (in\[MeV\]) of \[_{26}F{{e}^{56}}\] to \[_{83}B{{i}^{209}}\]? \[(1\,\,amu=931.5\,MeV)\]

Answer:

7.84