JEE Main & Advanced Sample Paper JEE Main - Mock Test - 38

  • question_answer
    The de-Broglie wavelength of a neutron at \[927{}^\circ C\] is\[\lambda \]. What will be its wavelength at\[27{}^\circ C\]?

    A) \[\lambda /2\]                

    B) \[\lambda \]

    C) \[2\lambda \]      

    D)        \[4\lambda \]

    Correct Answer: C

    Solution :

    [c] \[\lambda =\frac{h}{mv}\]     \[V\propto \sqrt{T}\] \[\lambda =\frac{h}{m\times \sqrt{1200}}\]                     ?......(1) \[{{\lambda }_{1}}=\frac{h}{m\times \sqrt{300}}\]                     ??.(2) Eq. \[\frac{2}{1}\]        


You need to login to perform this action.
You will be redirected in 3 sec spinner