A) \[1000.173{}^\circ C\]
B) \[100.0173{}^\circ C\]
C) \[100.173{}^\circ C\]
D) None
Correct Answer: B
Solution :
[b] \[w=6g,\text{ }W=1000g,\] Mol. wt. of glucose = 180 \[\Delta {{T}_{b}}=\frac{1000\times {{K}_{b}}\times w}{m\times W}\] \[=\frac{1000\times 0.52\times 6}{180\times 1000}=0.0173{}^\circ C\]. Hence boiling point of solution = b.p. of water + \[\Delta {{T}_{b}}=100+0.0173=100.0173{}^\circ C.\]
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