A) \[{{H}_{3}}C-\underset{H}{\overset{{{C}_{2}}{{H}_{5}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{2}}Br\xrightarrow[{{S}_{{{N}^{1}}}}]{O{{H}^{-}}}\]
B) \[C{{D}_{3}}-\overset{{{C}_{2}}{{H}_{5}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,H-C{{H}_{2}}Br~\xrightarrow[{{S}_{{{N}^{1}}}}]{O{{H}^{-}}}\]
C)
D) All of these
Correct Answer: B
Solution :
[b] Due to formation of chiral
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