JEE Main & Advanced Sample Paper JEE Main - Mock Test - 38

  • question_answer
    The standard free energy change for the reaction: \[{{H}_{2}}\left( g \right)+2AgC{{l}_{(s)}}\xrightarrow{{}}2A{{g}_{\left( s \right)}}+2{{H}^{+}}_{\left( aq \right)}+2C{{l}^{-}}_{(aq)}\] is \[-10.26\] kcal \[mo{{l}^{-1}}\] at\[25{}^\circ C\]. A cell using above reaction is operated at \[25{}^\circ C\] under \[{{P}_{{{H}_{2}}}}=1\] atm, \[[{{H}^{+}}]\] and \[\left[ C{{l}^{-}} \right]=0.1.\] Calculate e.m.f. of cell.

    Answer:

    0.34


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