A) \[2\pi r{{\rho }_{2}}gh\]
B) \[\frac{{{\rho }_{2}}rgh}{2}\]
C) \[\frac{gh({{\rho }_{1}}-{{\rho }_{2}})r}{2}\]
D) \[2pr({{\rho }_{2}}-{{\rho }_{1}})\]
Correct Answer: C
Solution :
[c] Angle of contact = zero R = radius of capillary = r Equating pressure at interface \[{{P}_{atm}}+\left( h\,\,{{\rho }_{1}}\,\,g \right)={{P}_{atm}}-\frac{2T}{R}+\left( h\,\,{{\rho }_{2}}\,\,g \right)\] \[T=\frac{gh\,\left( {{\rho }_{1}}-{{\rho }_{2}} \right)r}{2}\]You need to login to perform this action.
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