A) \[\frac{25\,m}{24\,hR}\]
B) \[\frac{24\,m}{25\,hR}\]
C) \[\frac{150\,hR}{25\,m}\]
D) \[\frac{25\,hR}{24\,m}\]
Correct Answer: C
Solution :
[c] Energy of photon \[=\frac{hc}{\lambda }=hcR\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{5}^{2}}} \right)=\frac{24hcR}{25}\] Momentum of photon \[=\frac{E}{c}=\frac{24hR}{25}\] =Momentum of atom Velocity of atom \[=\frac{24hR}{25m}\]where m = mass of atom.You need to login to perform this action.
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